Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Practice - Page 348: 7

Answer

$\frac{z^{5}}{y^{9}}$

Work Step by Step

We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer). Therefore, $\frac{y^{-9}}{z^{-5}}=\frac{1}{y^{9}}\times z^{5}=\frac{z^{5}}{y^{9}}$.
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