Answer
a.$ x^{3}$
b. $81y^{16}$
c. $\frac{x^3}{64}$
Work Step by Step
a. When dividing $x^{7}$ by $x^{4}$, you simply subtract the exponents because the base number/variable is the same. So 7-4 equals 3.
b.$(3y^{4})^4$ Simply multiply the exponent by the base number within the parentheses. 3 has an understood exponent of 1. y has an exponent of 4. $3^4$ equals 81. $(y^4)^4$ equals $y^{16}$.
c. This is similar to the last problem. x gets cubed, so it's $x^3$. 4 gets cubed as well, which equals 64. It remains as a fraction and can't be reduced.
