Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.3 - Solving Systems of Linear Equations by Addition - Exercise Set: 2

Answer

$x=3$ $y=1$

Work Step by Step

$\begin{cases} 4x+y=13\\2x-y=5\end{cases}$ Add both equations to eliminate the $y$: $6x=18$ Solve for $x$: $x=\dfrac{18}{6}=3$ Substitute $x=3$ in the first equation: $4(3)+y=13$ Solve for $y$: $12+y=13$ $y=13-12=1$ Our solutions are: $x=3$ $y=1$
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