Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.6 - Graphing Linear Inequalities in Two Variables - Practice - Page 261: 5

Answer

Please see the graph, made using graphing software.

Work Step by Step

$3x+2y\geq12$ $3x+2y=12$ Let $x=0$ $3x+2y=12$ $3*0+2y=12$ $0+2y=12$ $2y/2=12/2$ $y=6$ Let $y=0$ $3x+2y=12$ $3x+2*0=12$ $3x=12$ $3x/3 = 12/3$ $x=4$ $(0,6)$ and $(4,0)$ are on the boundary line. Use $(0,0)$ as the test point for shading. $3x+2y\geq12$ $3*0+2*0 \geq 12$ $0+0 \geq 12$ $0 \geq 12$ is a false statement, so we shade the side of the line without $(0,0)$.
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