Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 254: 62

Answer

a) $y=17500x+875000$ b) 1,015,000 restaurants

Work Step by Step

a) 2008 had 945,000 restaurants 2004 had 875,000 restaurants $2004-2004=0$ $2008-2004 = 4$ $(0,875000)$ and $(4,945000)$ are on the line $m= (945000-875000)/(4-0)$ $m= 70000/4$ $m=17500$ $y=17500x+b$ $875000=17500*0+b$ $875000=0+b$ $y=17500x+875000$ b) $2012-2004=8$ $y=17500x+875000$ $y=17500*8+875000$ $y=140000+875000$ $y=1015000$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.