Answer
points on the graph $$(2,\frac{2}{3}),(1,\frac{1}{3}),(-1,-\frac{1}{3}),(-2,-\frac{2}{3})$$
Work Step by Step
$$x = 3y$$
We can graph the equation by setting arbitrary values for $x$.
If $x=0$
$$x = 3y$$ $$0 = 3y$$ $$y=0$$
We then have point $(0,0)$.
If $x=-2$
$$x = 3y$$ $$-2 = 3y$$ $$y=-\frac{2}{3}$$
We then have point $(-2,-\frac{2}{3})$.
If $x=-1$
$$x = 3y$$ $$-1 = 3y$$ $$y=-\frac{1}{3}$$
We then have point $(-1,-\frac{1}{3})$.
If $x=1$
$$x = 3y$$ $$1 = 3y$$ $$y=\frac{1}{3}$$
We then have point $(1,\frac{1}{3})$.
If $x=2$
$$x = 3y$$ $$2 = 3y$$ $$y=\frac{2}{3}$$
We then have point $(2,\frac{2}{3})$.
