Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.3 - Further Solving Linear Equations - Exercise Set: 62

Answer

x = $\frac{15}{2}$

Work Step by Step

$\frac{5}{9}x + 2 - \frac{1}{6}x = \frac{11}{18}x + \frac{1}{3}$ Combine like terms: $\frac{7}{18}x + 2 = \frac{11}{18}x + \frac{1}{3}$ Subtract $\frac{11}{18}x$ from both sides: $-\frac{4}{18}x + 2 = \frac{1}{3}$ $-\frac{2}{9}x + 2 = \frac{1}{3}$ Subtract 2 from both sides: $-\frac{2}{9}x = -\frac{5}{3}$ Multiply both sides by $-\frac{9}{2}$: $-\frac{9}{2}(-\frac{2}{9}x) = (-\frac{5}{3})(-\frac{9}{2})$ x = $\frac{15}{2}$
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