Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.1 - The Additon Property of Equality - Exercise Set: 29

Answer

x = $-\frac{1}{2}$

Work Step by Step

$\frac{3}{8}x - \frac{1}{6} = -\frac{5}{8}x - \frac{2}{3}$ Add $\frac{5}{8}x$ to both sides: $\frac{8}{8}x - \frac{1}{6} = -\frac{2}{3}$ x - $\frac{1}{6} = -\frac{2}{3}$ Add $\frac{1}{6}$ to both sides: x = $-\frac{2}{3} + \frac{1}{6}$ x = $-\frac{4}{6} + \frac{1}{6}$ x = $-\frac{1}{2}$ Check with substitution: $\frac{3}{8}(-\frac{1}{2}) - \frac{1}{6} = -\frac{5}{8}(-\frac{1}{2}) - \frac{2}{3}$ $-\frac{3}{16} - \frac{1}{6} = \frac{5}{16} - \frac{2}{3}$ $-\frac{1}{6} = \frac{8}{16} - \frac{2}{3}$ $-\frac{1}{6} + \frac{2}{3} = \frac{8}{16} $ $\frac{1}{2} = \frac{1}{2}$
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