Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Section 13.1 - The Parabola and the Circle - Practice: 40

Answer

$(x+7)^{2}$ + $(y-6)^{2}$ = 4

Work Step by Step

In this problem, $h$ is -7, $k$ is 6, and $r$ is 2. Given the equation $(x-h)^{2}$ + $(y-k)^{2}$ = $r^{2}$, the equation of this circle would be $(x-(-7))^{2}$ + $(y-(6))^{2}$ = $2^{2}$, or $(x+7)^{2}$ + $(y-6)^{2}$ = $4$.
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