Answer
It is a parabola with vertex at (3, -2).
See Graph I for the graphing of the equation.
Work Step by Step
For $x = -(y + 2)^2 + 3$, it is in the form of a parabola.
Since the coefficient of $y^2$ is negative, the parabola opens to the left. The vertex is at (3, -2).
When $y = 0$, $x = -1$, the $x-intercept$ is at -1.
See Graph I for the graphing of the equation.