Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Test - Page 911: 29

Answer

6% compounded monthly for 10 years 229.32 more

Work Step by Step

6.5% compounded twice a year for 10 years $(1+(.065/2))^{10*2}$ $1.0325^{20}$ $1.8958379$ 6% compounded monthly for 10 years $(1+(.06)/12)^{10*12}$ $1.005^{120}$ $1.81939673$ $1.8958379*3000=5687.51$ $1.81939673*3000=5458.19$ $5687.51-5458.19=229.32$ The 6.5% compounded twice a year earns 229.32 more than the 6% compounded monthly.
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