Answer
$f^{-1}$(x)=$\frac{2x+3}{4}$
Work Step by Step
f(x)=$\frac{4x-3}{2}$
y=$\frac{4x-3}{2}$
x=$\frac{4y-3}{2}$
2x=4y-3
2x+3=4y
y=$\frac{2x+3}{4}$
$f^{-1}$(x)=$\frac{2x+3}{4}$
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