Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review - Page 908: 91

Answer

{$2\sqrt 2$}

Work Step by Step

Step 1: $\log_{2} x+\log_{2} 2x-3=1$ Step 2: $\log_{2} (x\times2x)=1+3$ Step 3: $\log_{2} (2x^{2})=4$ Step 4: $2x^{2}=2^{4}$ Step 5: $2x^{2}=16$ Step 6: $x^{2}=8$ Step 7: $x=\sqrt 8=2\sqrt 2$ Therefore, the solution set is {$2\sqrt 2$}.
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