Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Test - Page 833: 19

Answer

The vertex is (2,0) X-intercept: (2,0) Y intercept: (0,4)

Work Step by Step

Y Intercept: Plug in 0 for all x values and solve for y. y=x^2-4x+4 y=0^2-4(0)+4 y=0-0+4 y=0+4 y=4 (0,4) X-Intercept: Plug in 0 for the y value and solve for x. 0=x^2-4x+4 factor the equation and get (x-2)^2=0 x-2=0 add 2 to both sides x=2 (2,0) Vertex: Find your A, B, and C values. For the equation h(x)= x^2-4x+4.... A=1, B=-4, and C=4 formula for finding the x value of the vertex is: X= -B/2a X= -(-4)/2(1) X= 4/2 X=2 So since you now have your x value, which is 2, plug 2 into the x values of your equation. H(2)= (2)^2-4(2)+4 H(2)= 4 - 8 + 4 H(2) = -4 + 4 H(2) = 0 Vertex: (2,0)
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