Answer
$x=-3\pm\sqrt{11}$
Work Step by Step
$x(x+6)=2$
Evaluate the product on the left side of the equation:
$x^{2}+6x=2$
Take the $2$ to the left side:
$x^{2}+6x-2=0$
Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. Here, $a=1$, $b=6$ and $c=-2$
Substitute:
$x=\dfrac{-6\pm\sqrt{6^{2}-4(1)(-2)}}{2(1)}=\dfrac{-6\pm\sqrt{36+8}}{2}=...$
$...=\dfrac{-6\pm\sqrt{44}}{2}=\dfrac{-6\pm2\sqrt{11}}{2}=-3\pm\sqrt{11}$
