Answer
$x=(-1+\sqrt 6, -1-\sqrt 6)$
Work Step by Step
Step-1 : Add $5$ on both sides of the equation
$x^2+2x=5$
Step -2 : Add the square of half of the co-efficient of $x$ to both sides.
Co-efficient of $x =2$
Half of $2 = \frac{1}{2}×2=1$
Square of $1$ is $1×1=1$
The equation becomes $x^2+2x+1=5+1$
Step-3 Factor the trinomial and simplify the right hand side.
$(x+1)^2=6$
Step-4 Use the square root property and solve for $x$
$(x+1)=±\sqrt 6 $
Step-5 Subtract 1 on both the sides
$x=-1±\sqrt 6$
Therefore the solution set is $(-1+\sqrt 6, -1-\sqrt 6)$
