Answer
One real solution
Work Step by Step
Since the discriminant ($b^2-4ac$) is equal to 0, the quadratic equations has one real solution:
$\dfrac{-b\pm \sqrt{b^2-4ac}}{2a} = \dfrac{-b\pm \sqrt{0}}{2a} = \dfrac{-b\pm 0}{2a} = -\dfrac{b}{2a}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Review - Page 828: 12
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