Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Cumulative Review: 20

Answer

$\frac{b+2a}{2b+a}$

Work Step by Step

$\frac{(2a)^{-1}+(b)^{-1}}{(a)^{-1}+(2b)^{-1}}$ =$\frac{\frac{1}{2a}+\frac{1}{b}}{\frac{1}{a}+\frac{1}{2b}}$ =$\frac{\frac{b+2a}{2ab}}{\frac{2b+a}{2ab}}$ =$\frac{b+2a}{2ab}\div\frac{2b+a}{2ab}$ =$\frac{b+2a}{2ab}\times \frac{2ab}{2b+a}$ =$\frac{b+2a}{2b+a}$
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