Answer
$\frac{3}{13}+\frac{11i}{13}$
Work Step by Step
$\frac{3+i}{2-3i}$
$\frac{2+3i}{2+3i}*\frac{3+i}{2-3i}$
$\frac{2+3i}{2+3i}*\frac{3+i}{2-3i}$
$\frac{2*3+2*i+3i*3+3i*i}{2*2+2*(-3i)+3i*2+3i*(-3i)}$
$\frac{6+2*i+9i+3i^2}{4-6i+6i-9i^2}$
$\frac{6+11i+3(-1)}{4-9i^2}$
$\frac{6+11i-3}{4-9(-1)}$
$\frac{3+11i}{4+9}$
$\frac{3+11i}{13}$
