Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 1 - Section 1.5 - Subtracting Real Numbers - Exercise Set - Page 45: 27

Answer

$-\frac{1}{6}$

Work Step by Step

$\frac{1}{2}-\frac{2}{3}=\frac{1\times3}{2\times3}-\frac{2\times2}{3\times2}=\frac{3}{6}-\frac{4}{6}=\frac{3-4}{6}=\frac{3+(-4)}{6}=\frac{-1}{6}=-\frac{1}{6}$
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