Algebra: A Combined Approach (4th Edition)

$x = 1$ $y = -1$
$4x - y = 5$ $3x - 3 = 0$ Therefore $4x - y = 5$ $3x = 3$ $a = 4$ , $b = -1$, $c = 3$, $d = 0$, $h = 5$, $k = 3$ lets calculate $D = ad-bc = 0 + 3= 3$ $D_x = hd-bk = 0+3 = 3$ $D_y = ak-ch= 12-15= -3$ Therefore by Cramer's rule, $x = \frac{D_x}{D} = \frac{3}{3} = 1$ $y = \frac{D_y}{D} = \frac{-3}{3} = -1$