Answer
$(-∞,-\frac{8}{3}]\cup(2,∞)$
Work Step by Step
We simplify as follows:
$\frac{3}{8}x+1\leq0$ or $-2x\lt-4$
$\frac{3}{8}x\leq-1$ or $x\gt2$
$x\leq-\frac{8}{3}$ or $x\gt2$
$(-∞,-\frac{8}{3}]\cup(2,∞)$
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