Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Skills Handbook - Area and Volume - Exercises - Page 976: 6

Answer

$\frac{2048}{3}\pi \ in^3$

Work Step by Step

We have a sphere, and we know the radius, $r = 8$ in. $V = \frac{4}{3}\pi r^3$ $V = \frac{4}{3}\pi*8^3 = \frac{2048}{3}\pi \ in^3$
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