Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Cumulative Standards Review - Multiple Choice - Page 275: 5

Answer

$B$

Work Step by Step

Use the rule $|x|=a \implies x=a \text{ or } x=-a$ to obtain: $3x - 5 = 2\quad$ or $\quad3x - 5 = -2$ Solve each equation. For the first equation we have: $3x - 5 = 2$ $3x = 2+5\\ 3x=7$ Divide both sides of the equation by $3$ to solve for $x$: $x = \frac{7}{3}$ For the second equation: $3x - 5 = -2\\ 3x=-2+5$ $3x = 3$ Divide both sides of the equation by $3$ to solve for $x$: $x = 1$ Thus, the solutions are $x = \frac{7}{3}$ and $x = 1$. This corresponds to option $B$.
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