Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-5 Systems With Three Variables - Practice and Problem-Solving Exercises - Page 173: 56

Answer

$\text{no solution}$

Work Step by Step

Rewrite both equations so that all the variables are on one side of the equation and the constants are on the other: $-2x + 4y = 6$ $-4x + 8y = -12$ We need to modify one equation so that one of the variables is the same in both equations but differing in sign. Let us multiply the first equation by $-2$ to obtain the equivalent system $4x - 8y = -12$ $-4x + 8y = -12$ Add the equations together: $(4x-8y)+(-4x+8y) = -12+(-12)$ $0=-24$ This statement is false, which means that the system of equations has no real solutions because the lines are parallel to each other and never intersect each other.
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