Chapter 3 - Linear Systems - 3-1 Solving Systems Using Tables and Graphs - Practice and Problem-Solving Exercises - Page 141: 67

(a) $y = -3$ (b) $y = 8$ (c) $y = -10$

(a) We plug in $-3$ in for $x$ into the equation to find $y$: $y = 2(-3) + 3$ $y = -6 + 3$ $y = -3$ (b) We plug in $-3$ in for $x$ into the equation to find $y$: $y = -(-3) + 5$ $y = 3 + 5$ $y = 8$ (c) We plug in $-3$ in for $x$ into the equation to find $y$: $y = 3(-3) - 1$ $y = -9 - 1$ $y = -10$