Answer
-5, 1, 4, and 13
Work Step by Step
We substitute the values in.
$3(-2)+1=-6+1=-5$
$3(0)+1=0+1=1$
$3(1)+1=3+1=4$
$3(4)+1=12+1=13$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 2 - Functions, Equations, and Graphs - 2-2 Direct Variation - Practice and Problem-Solving Exercises - Page 73: 72
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