Answer
The probability of rolling each of 1, 3, 5, 6 is 1/10, and the probability of rolling each of 2, 4 is 3/10.
Work Step by Step
We are given that $p_2 = 3p_1$ (for instance), $p_2 = p_4$, and $p_1 = p_3 = p_5 = p_6$. Since the probabilities sum to 1, we can write $p_1 + 3p_1 + p_1 + 3p_1 + p_1 + p_1 = 1$, so $10p_1 = 1$ and $p_1 = 1/10$.
So the probability of rolling each of 1, 3, 5, 6 is 1/10, and the probability of rolling each of 2, 4 is 3/10.
