Answer
Have to Point Out What is wrong with this “proof” by strong induction?
--“Theorem” For every non negative integer n, 5n = 0.
Basis Step: 5 · 0 = 0.
Work Step by Step
-The error is in going from the base case n = 0 to the nextcase, n = 1;
-we cannot write 1 as the sum of two smaller natural numbers.
