Answer
The function is evaluated at few values and then plotted on the corresponding points on a set of axis. the graph is drawn
Work Step by Step
Given: $f : \mathbf{Z} \rightarrow \mathbf{Z}$
Note that the function is defined from $Z$ to $Z$, which means that the function is only defined for integers.
Let us evaluate the function at a few points:
$f(-4)=1-(-4)^{2}=1-16=-15$
$f(-3)=1-(-3)^{2}=1-9=-8$
$f(-2)=1-(-2)^{2}=1-4=-3$
$f(-1)=1-(-1)^{2}=1-1=0$
$f(0)=1-0^{2}=1$
$f(1)=1-1^{2}=1-1=0$
$f(2)=1-2^{2}=1-4=-3$
$f(3)=1-3^{2}=1-9=-8$
$f(4)=1-4^{2}=1-16=-15$
The corresponding Points of the graph are then $(-4,-15),(-3,-8),(-2,-3)$ $(-1,0),(0,1),(1,0),(2,-3),(3,-8),(4,-15)$
Draw these points on a set of coordinate axes (note: do not connect the.points by a Solid line, because the function is only defined for integer values n)
