# Chapter 1 - 1.7 - Problems - Introduction to Circuits: P1.63

$v_x=17.5V #### Work Step by Step Ohm's law dictates$v_2=5V$and since all three resistors are in parallel we can find that$i_2=v_2\div 10\Omega=.5A$and$i_3=v_2\div5\Omega=1A$Then, using KCL in conjunction with Ohm's law,$v_1=5\Omega\times(1A+1A+0.5A)=12.5V$Finally, with KVL we can find$v_x-v_1-v_2=0, v_x=12.5V+5V=17.5V\$

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