Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 34 - Ray Optics - Exercises and Problems - Page 993: 59

Answer

$v = 2.7~m/s$

Work Step by Step

We can find the shark's actual speed $v$: $s = (\frac{n_1}{n_2})~s'$ $\frac{ds}{dt} = (\frac{n_1}{n_2})~\frac{ds'}{dt}$ $v = (\frac{n_1}{n_2})~v'$ $v = (\frac{1.33}{1.00})~(2.0~m/s)$ $v = 2.7~m/s$
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