Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Section 10.3 - Rotational Inertia and the Analog of Newton’s Law - Example - Page 182: 10.6

Answer

$I = MR^2$

Work Step by Step

We take the integral to find: $I = \int R^2dm$ R is constant for a ring, so we can take it out of the integral. $I = R^2\int dm$ $I = MR^2$
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