Answer
The correct structure for each compound is as follows:
Work Step by Step
Question a: Step 1 - Hex means 6.. Here, no. of C in straight chain = 6. draw 6 C in a straight chain and join them with single bond and numbering the C from 1 to 6 from left side to right side. Find the ending name. Here,the ending name is ene. That means a double bond is present in the compound. The number 2 in 2-hexene suggests that the double bond will be between no. 2 and no. 3 Carbon. In step 2, place a double bond between no. 2 and no. 3 Carbon. The remaining valency of Carbon is then fulfilled by H in step 3.
Question b: step 1 - find the no. of C in straight chain. Hept means 7. Draw 7 Carbons in a straight chain and join them with single bond and numbering every carbon from left to right. In step 2, place triple bond (ending name 'yne') in between no. 3 and no. 4 Carbon (3-heptyne). In step 3, remaining valency will be fulfilled by H.
Question C: Step 1 - Draw 5 Carbons in a straight chain and join them with single bond (pent = 5) and numbering them from left to right. In step 2, place triple bond (ending name 'yne') in between no. 1 and no. 2 Carbon. In step 3, place a methyl group in no. 3 Carbon . In step 4, fill the remaining valency with H.
Question d: Step 1 - draw 6 C in a straight chain and join them with single bond (hex = 6) and numbering them from left to right. In step 2, place double bond (ending name 'ene') in between no. 2 and no. 3 Carbon. In step 3, place two no. of methyl group in position 4 (4,4-dimethyl). In step 4, the remaining valency will be filled with H. See the every step in pictures below:
