Answer
a. Final concentration = $2.0 \space M \space HCl$
b. Final concentration = $2.0 \space M \space NaOH$
c. Final concentration = $2.5\% \space (m/v) \space KOH$
d. Final concentration = $3.0\% \space (m/v) \space H_2SO_4$
Work Step by Step
1. Write the dilution expression, and solve for the final concentration $(C_2)$
$C_1V_1 = C_2V_2$
$$\frac{C_1V_1}{V_2} = C_2$$
a.
2. Substitute the values and calculate the final concentration:
$$C_2 = \frac{(6.0 \space L)(2.0 \space M)}{6.0 \space L}$$
$$C_2 = 2.0 \space M$$
b.
2. Substitute the values and calculate the final concentration:
$$C_2 = \frac{(12 \space L)(0.50 \space M)}{3.0 \space L}$$
$$C_2 = 2.0 \space M$$
c.
2. Substitute the values and calculate the final concentration:
$$C_2 = \frac{(25 \space mL)(10.0 \space \% (m/v))}{100.0 \space mL}$$
$$C_2 = 2.5 \space \% (m/v)$$
d.
2. Substitute the values and calculate the final concentration:
$$C_2 = \frac{(15 \space mL)(50.0 \space \% (m/v))}{250 \space mL}$$
$$C_2 = 3.0 \space \% (m/v)$$
