Answer
a. 5.00 moles of $O_2$
b. 7.0 moles of $CO_2$
c. 0.50 mole of $C_2H_2$
d. 0.0800 mole of $CO_2$
Work Step by Step
a. Find the conversion factors, and calculate the amount of $ O_2 $ moles
$ C_2H_2 $ and $ O_2 $: $$ \frac{ 2 \space moles \space C_2H_2 }{ 5 \space moles \space O_2 } \space and \space \frac{ 5 \space moles \space O_2 }{ 2 \space moles \space C_2H_2 }$$
$$ 2.00 \space moles \space C_2H_2 \times \frac{ 5 \space moles \ O_2 }{ 2 \space moles \space C_2H_2 } = 5.00 \space moles \space O_2 $$
b. Find the conversion factors, and calculate the amount of $ CO_2 $ moles
$ C_2H_2 $ and $ CO_2 $: $$ \frac{ 2 \space moles \space C_2H_2 }{ 4 \space moles \space CO_2 } \space and \space \frac{ 4 \space moles \space CO_2 }{ 2 \space moles \space C_2H_2 }$$
$$ 3.5 \space moles \space C_2H_2 \times \frac{ 4 \space moles \ CO_2 }{ 2 \space moles \space C_2H_2 } = 7.0 \space moles \space CO_2 $$
c. Find the conversion factors, and calculate the amount of $ C_2H_2 $ moles
$ H_2O $ and $ C_2H_2 $: $$ \frac{ 2 \space moles \space H_2O }{ 2 \space moles \space C_2H_2 } \space and \space \frac{ 2 \space moles \space C_2H_2 }{ 2 \space moles \space H_2O }$$
$$ 0.50 \space mole \space H_2O \times \frac{ 2 \space moles \ C_2H_2 }{ 2 \space moles \space H_2O } = 0.50 \space mole \space C_2H_2 $$
d. Find the conversion factors, and calculate the amount of $ CO_2 $ moles
$ O_2 $ and $ CO_2 $: $$ \frac{ 5 \space moles \space O_2 }{ 4 \space moles \space CO_2 } \space and \space \frac{ 4 \space moles \space CO_2 }{ 5 \space moles \space O_2 }$$
$$ 0.100 \space mole \space O_2 \times \frac{ 4 \space moles \ CO_2 }{ 5 \space moles \space O_2 } = 0.0800 \space mole \space CO_2 $$
