General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 5 - Nuclear Chemistry - 5.2 Nuclear Reactions - Questions and Problems: 5.20

Answer

a) $^{11}_6$C --> $^{11}_5$B + $^0_{+1}$e ; Positron Emission b) $^{35}_{16}$S -->$^{35}_{17}$Cl + $^0_{-1}$e ; Beta Decay c) $^{90}_{38}$Sr --> $^{90}_{39}$Y + $^0_{-1}e$ ; Beta Decay d) $^{210}_{83}$Bi --> $^{206}_{81}$Tl + $^4_2$He ; Alpha Decay e) $^{89}_{40}$Zr --> $^{89}_{39}$Y + $^0_{+1}$e ; Positron Emission

Work Step by Step

a) The atomic number went down by one, but the mass number remained the same, so the missing particle is a Positron ($^0_{+1}$e), thus making it a Positron Emission reaction. b) There was a Beta Particle (negative charge) emitted on the other side of the equation, so the resulting isotope would have an atomic number of +1 to the original, which is indicative of Beta Decay. c) The product side of the equation shows $^{90}_{39}$Y + $^0_{-1}e$ which means the original isotope had an atomic number that was one less than the product. The presence of a Beta Particle is indicative of a Beta Decay reaction. d) An Alpha Particle ($^4_2$He) is part of the product, which is indicative of an Alpha Decay reaction. To balance the equation and find the missing isotope, we must subtract 4 from the mass number and 2 from the atomic number of the original isotope. e) The product in this reaction is a Positron and an isotope, which means this was a Positron Emission reaction. To balance to equation the original isotope will have the same mass number but one must be added to the atomic number of the product isotope.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.