General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 4 - Atoms - Challenge Questions: 4.124


a) $^{107}_{47}$Ag: 47 protons, 60 neutrons, 47 electrons b)$^{109}_{47}$Ag c)$^{109}_{48}$Cd

Work Step by Step

a) Ag (Silver) has an atomic number of 47, which is shown in subscript, so it has 47 protons and 47 electrons. This particular isotope has a mass number of 107, which is the sum of the protons and neutrons, so if you subtract 47 from the mass number, you get 60 neutrons. b) If you have an isotope of Silver (Ag) with 62 neutrons, its mass number would be 109; thus, the atomic symbol for that isotope would be $^{109}_{47}$Ag. c) If you had an atom of an isotope with a mass number of 109, such as the one in part b, but it had 61 neutrons instead of 62, then the atomic number would be 48, which corresponds with Cadmium (Cd) on the Periodic Table and is expressed like so: $^{109}_{48}$Cd.
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