Answer
$T_2$ would be lower than $T_1$ for the reaction shown in the diagrams.
Work Step by Step
1. Since the heat is on the products side, the reaction is exothermic.
- Therefore, if the temperature increases, the equilibrium shifts in the diretion of the reactants, and vice-versa.
2. Count the amount of product molecules at $T_1$ and $T_2$:
$T_1$ : 2 molecules
$T_2$: 8 molecules
- The equilibrium shifted in the direction of the products. Therefore, the temperature decreased.