## General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal

# Chapter 3 - Chemical Compounds - Exercises - The Avogadro Constant and the Mole - Page 103: 5

#### Answer

(a) The molecule contains 7 C atoms, 5 H atoms, 3 N atoms, and 6 O atoms; total: 21 atoms (b) 0.00102 mol of $CH_{3}(CH_{2})_{4}CH_{2}OH$ contains $1.29 x 10^{22}$ atoms (c) There are $2.19 x 10^{25}$ F atoms in 12.15 mol $C_{2}HBrClF_{3}$

#### Work Step by Step

Count the number of atoms per molecule and then use molar mass to calculate the number of atoms in the given weight.

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