Answer
The formula for compound is given as Cr(NO3)3 . 9H2O
Molecular mass= 52 g + (3 x 14 g) + (3x3x16 g) + (9 x 18 g) = 400 g
Mass of H2O in the molecule= 162 g
Mass % of H2O=[mass of H2O]/[mass of Cr(NO3)3 . 9H2O] x 100 = 162/400 x 100 = 40.5 %
mass percent of H2O in the given hydrate = 40.5 %
Work Step by Step
1. Calculate the molecular mass of the given compound
2. Find the mass of water
3. Using the formula for mass percent, Mass % of H2O= (mass of H2O)/(mass of Cr(NO3)3.9H2O) x 100 and substituting the values, the mass percent of H2O is calculated.
4. The mass percent of H2O in the isooctane is 40.5 %
