#### Answer

36.18%

#### Work Step by Step

Using the molar mass, it follows:
Mass percent O= $\frac{5\,mol\,O\times\frac{15.999\,g\,O}{1\,mol\,O}}{221.1\,g\,malachite}\times100\%$
$=36.18\%$

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Published by
Pearson Prentice Hal

ISBN 10:
0132064529

ISBN 13:
978-0-13206-452-1

36.18%

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