General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 3 - Chemical Compounds - Exercises - Percent Composition of Compounds - Page 104: 19

Answer

15.585%

Work Step by Step

Mass of H in the compound = $22\times1.008g$ = 22.176 g Molar mass of $C_{10}H_{22}$ = $(10\times12.011g)+(22\times1.008g)$ = 142.29 g Mass % of H = (Mass of H in $C_{10}H_{22}$$\times$100)/(Molar mass of $C_{10}H_{22}$) = $\frac{22.176g\times100}{142.29g}$ = 15.585%
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