General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 2 - Atoms and the Atomic Theory - Exercises - Law of Conservation of Mass - Page 60: 3


$mass_{O_{2}}$ = 0.268 g

Work Step by Step

The mass of the products and the mass of the reactants are equal. This is stated in the Law of Conservation of Mass. So $mass_{products}$ = $mass_{reactants}$ $mass_{Mg} + mass_{O_{2}} $ = $mass_{MgO}$ 0.406 + $mass_{O_{2}}$ = 0.674 $mass_{O_{2}}$ = 0.674 - 0.406 $mass_{O_{2}}$ = 0.268 g Rounding to three significant figures gives $mass_{O_{2}}$ = 0.268 g
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.