Answer
1) 0.60 mol NaCH3COO—choice , c—would raise the PH value because all HCL turns into CH3COOH, producing a buffer solution of (CH3COOH + NaCH3COO) whose PH $\approx 4$
2) Choices (a) and (b) do not change the PH
3) Though Choice (d) would neutralize 80% of the acid, the remaining 20% would still produce a PH$\approx1$
Work Step by Step
1) 0.60 mol NaCH3COO—choice , c—would raise the PH value because all HCL turns into CH3COOH, producing a buffer solution of (CH3COOH + NaCH3COO) whose PH $\approx 4$
2) Choices (a) and (b) do not change the PH
3) Though Choice (d) would neutralize 80% of the acid, the remaining 20% would still produce a PH$\approx1$