## General Chemistry: Principles and Modern Applications (10th Edition)

(a) $$K_p = 0.114$$ (b) $$K_p =4.26 \times 10^3$$ (c) $$K_p = 3.45 \times 10^{-4}$$
(a) T = 25 + 273.15 = 298.15 K $$K_p = K_c(RT)^{\Delta n} = 4.61 \times 10^{-3} (0.08314 \times 298.15)^{2 - 1} = 0.114$$ (b) $$K_p = K_c(RT)^{\Delta n} =0.154 (0.08314 \times 2000)^{4 - 2} = 4.26 \times 10^3$$ (c) $$K_p = K_c(RT)^{\Delta n} =(5.27 \times 10^{-8}) (0.08314 \times 973)^{5 - 3} = 3.45 \times 10^{-4}$$