General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 15 - Priciples of Chemical Equilibrium - Exercises - Writing Equilibrium Contants Expressions - Page 688: 7

Answer

(a) $$K_c = 1.2 \times 10^{-3}$$ (b) $$K_c = 5.63 \times 10^{5}$$ (c) $$K_c = 7.24 \times 10^{-3}$$

Work Step by Step

(a) $$K_c = \frac{K_p}{RT^{\Delta n}} = \frac{2.9 \times 10^{-2}}{(0.08314 \times 303)^{2-1}} = 1.2 \times 10^{-3}$$ (b) T = 184 + 273.15 = 457.15 K $$K_c = \frac{K_p}{RT^{\Delta n}} = \frac{1.48 \times 10^4}{(0.08314 \times 457.15)^{2-3}} = 5.63 \times 10^{5}$$ (c) $$K_c = \frac{K_p}{RT^{\Delta n}} = \frac{0.429}{(0.08314 \times 713)^{5 - 4}}= 7.24 \times 10^{-3}$$
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