Answer
We cannot conclude if the numerical value of K for this reaction is greater or less than the same for the other reaction.
Work Step by Step
We know that, since the first reaction (1) is just the same reaction as the second one (2), but with the coefficients multiplied by 2:
$$K_1 = K_2^2$$
Thus, if $K_2 \gt 1$, $K_1 \gt K_2$, but, if $K_2 \lt 1$, then $K_2 \gt K_1$.
