General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 15 - Priciples of Chemical Equilibrium - 15-2 Concept Assessment - Page 660: 15-2

Answer

$$K = \frac{a_{Cu^{2+}}a_{H_2}}{a{^2}_{H^+}}$$ $$K \approx \frac{[Cu^{2+}]_{eq}P_{H_2}}{[H^+]_{eq}^2}$$

Work Step by Step

$$K = \frac{a_{Cu^{2+}}a_{H_2}}{a{^2}_{H^+}}$$ $$a_{Cu^{2+}} = \frac{\gamma_{Cu^{2+}}[Cu^{2+}]_{eq}}{c^o}$$ $$a_{H_2} = \frac{\gamma_{H_2}P_{H_2}}{P^o}$$ $$a_{H^{+}} = \frac{\gamma_{H^{+}}[H^{+}]_{eq}}{c^o}$$ $$K = \frac{(\frac{\gamma_{Cu^{2+}}[Cu^{2+}]_{eq}}{c^o})(\frac{\gamma_{H_2}P_{H_2}}{P^o})}{(\frac{\gamma_{H^{+}}[H^{+}]_{eq}}{c^o})^2} \approx \frac{[Cu^{2+}]_{eq}P_{H_2}}{[H^+]_{eq}^2}$$
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