Answer
$\sqrt 2$
Work Step by Step
Rate initially = Rate 1 = k$[A]^{1/2}$
Rate with double concentration [2A] = Rate2 =k $[2A]^{1/2}$
$\frac{Rate2}{Rate1}$ = $\frac{k[2A]^{1/2}}{k[A]^{1}}$
= $\sqrt 2$
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