## General Chemistry 10th Edition

$\sqrt 2$
Rate initially = Rate 1 = k$[A]^{1/2}$ Rate with double concentration [2A] = Rate2 =k $[2A]^{1/2}$ $\frac{Rate2}{Rate1}$ = $\frac{k[2A]^{1/2}}{k[A]^{1}}$ = $\sqrt 2$