General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 13 - Rates of Reaction - Exercises - Page 562: 13.8


$\sqrt 2$

Work Step by Step

Rate initially = Rate 1 = k$[A]^{1/2}$ Rate with double concentration [2A] = Rate2 =k $[2A]^{1/2}$ $\frac{Rate2}{Rate1}$ = $\frac{k[2A]^{1/2}}{k[A]^{1}}$ = $\sqrt 2$
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