#### Answer

$\sqrt 2$

#### Work Step by Step

Rate initially = Rate 1 = k$[A]^{1/2}$
Rate with double concentration [2A] = Rate2 =k $[2A]^{1/2}$
$\frac{Rate2}{Rate1}$ = $\frac{k[2A]^{1/2}}{k[A]^{1}}$
= $\sqrt 2$

Published by
Cengage Learning

ISBN 10:
1-28505-137-8

ISBN 13:
978-1-28505-137-6

$\sqrt 2$

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